Given an array nums
, write a function to move all 0
's to the end of it while maintaining the relative order of the non-zero elements.
Notice
- You must do this in-place without making a copy of the array.
- Minimize the total number of operations.
Example
Given nums = [0, 1, 0, 3, 12]
, after calling your function, nums
should be [1, 3, 12, 0, 0]
.
LeetCode上的原题,请参见我之前的博客。
解法一:
class Solution {public: /** * @param nums an integer array * @return nothing, do this in-place */ void moveZeroes(vector & nums) { for (int i = 0, j = 0; i < nums.size(); ++i) { if (nums[i]) { swap(nums[i], nums[j++]); } } }};
解法二:
class Solution {public: /** * @param nums an integer array * @return nothing, do this in-place */ void moveZeroes(vector & nums) { int left = 0, right = 0; while (right < nums.size()) { if (nums[right]) { swap(nums[left++], nums[right]); } ++right; } }};
本文转自博客园Grandyang的博客,原文链接:,如需转载请自行联系原博主。